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#!/bin/sh
m="$(date +%m)"
d="$(date +%d)"
y="$(date +%y)"
# Trying to make a regex that will match expac's date format
# 1. create ranges based on command line arguments
# 2. change this to \(n-2\|n-1\|n\)
# I. generate sequence
# II. remove trailing space
# III.translate space to '\|'
# IV. wrap everything in '\( ... \)'
# V. shift command line arguments
# repeat 2. for month and year
# 3. seq outputs a newline, translate this to slash
# 4. remove trailing slash
regex="$(for var in m d y
do
seq -w -s ' ' $((${!var} - ${1:-0})) ${!var} |
sed 's/ /\\|/g;s/.*/\\(&\\)/'
shift 2>/dev/null
done |
tr '\n' '/' |
sed 's/.$//')"
expac -t %D '%l %n' |
grep "$regex" |
sort -k 2 -t '/' -n
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